Math, asked by dasthagir, 5 months ago

the number obtained by reversing the order of the digits. Find the number.
(iv) Meena went to a bank to withdraw 3 2000. She asked the cashier to give her
50 and 100 notes only. Meena got 25 notes in all. Find how many notes of
50 and 100 she received. in. Elimenetion method​

Answers

Answered by 786muhammedjaffar786
1

Answer:

sorry did not understood this answer

Answered by Anonymous
5

 \huge \sf Answer :

Rs 50 notes = 10 and Rs 100 notes = 15

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 \huge \sf Solution :

Let total Rs 50 notes = x

and total Rs 100 notes = y

∴ Total notes = x + y

But we are given total notes = 25

\sf \implies x+y = 25 \: \: - ①

Now, Meena has total money =50x + 100y

But we are given total money =Rs 2000

\sf \implies 50x+100y=2000

\sf \implies 50(x+2y)=2000

\sf \implies x+2y = \dfrac{2000}{50}

\sf \implies x+2y = \dfrac{\cancel{2000}^{40}}{\cancel{50}}

\sf \implies x+2y = 40 \: \: - ②

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On substraction of ① and ②,

(x+y) - (x+2y) = 25 - 40

x + y - x - 2y = - 15

- y = - 15

\boxed{\sf y = 15}

Now, by putting y in ①,

x+y=25

x + 15 = 25

x = 25 - 15

\boxed{\sf x=10}

∴ Rs 50 notes, x = 10

and Rs 100 notes, y = 15

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