The number of 3 digit even numbers that can be formed from the digit 0,1,2,3,4and 5 ,repetition of digits being not allowed ,is
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option a. 1st digit can't be 0. 2nd and 3rd can be 0. So 5×5×4=60 is ans
ankit212:
I just know the answer .I want to know how it comes.
Is there any way to send pic of solution here in comments
i think there is no way .
Okay just hold on.
ok
case1: When last digit is 0: No. of ways of filling 1st and 2nd postn= 5×4=20. case 2: when last digit is not 0: then last digit can be either of 2 or 4. So there are 2 ways of filling last digit.0 cant be 1st digit as well. So no. of ways=4×4×2=32. TOTAL WAYS = 20 + 32= 52. HOPE U GET IT
thanks a lot
Which class are u in
I am undergraduate .
Thats great. Okay good bye
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