The number of 6-digit numbers that can be formed from 0, 1, 5, 6, 7 and 8 in which the first digit is not 0 are
Answers
ANSWER
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THERE ARE TO MANY NUMBER ARE FORM SUCH THAT ...........
501678,
501786,
501867,
507186,
508761,
ETC. LIKE THAT NUMBERS ARE FORM ....
HOPE ITS HELP U ......
THANKU ...
Answer:
Case 1:
Repeatition is allowed-
5 * 6^5 == 38,880
Case 2:
Repeatition is not allowed-
5* 5! == 600
Step-by-step explanation:
Case 1:
If repeatition is allowed:
The first digit i.e,first from left, place can take any non zero value(such as 1,5,6,7,8).
Total is 5 terms.
Now the second digits place can take any value (including zero) such as 0,1,5,6,7,8.
Total terms is 6.
Now the third digits place can take any value again.
Total is 6.
Similarly all the places upto 6 digits are occupied.
Therefore the total no. of possibilities of the answer is 5*6*6*6*6*6 == 38,880(Multiplying the total terms in each case, Fundamental Principle of counting)
Case 2:
Repeatition is not allowed.
First digit can take any non zero value .
Total is 5
Second digit can take any value other than the 1 value used for first digit.
Therefore total terms = 6-1 = 5
Third digit can take any value other than the 2 digits used first .
Total = 6-2 = 4
Similarly 4th digit can take 3 values, 5th digit 2 values and 6th digit can take 1 value
Therefore the total no. of possibilities are 5* 5*4*3*2*1 = 5* 5! == 600
Thank you and hope this helps.
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