Question

The number of 6 digit numbers that
can be formed using the digits 0,1,2,5,7
land 9 which emme livisible by H sind
digit is reported is
miltiple choice question​

Answer 1

Answer:

Therefore, the number of 6 digit numbers that can be formed using the digits 0,1,2,5,7 and 9 which are divisible by 11

Answer 2

Answer:

Sum of given digits 0,1,2,5,7,9 is 24.

Let the six digit number be abcdef and to be divisible by 11.

So ∣(s+c+e)−(b+d+f)∣ is multiple of 11.

Hence only possibility is a+c+e=12=b+d+f

Case - I {a,c,e}={9,2,1}&{b,d,f}={7,5,0}

So, Number of numbers =3!×3!=36

Case - II {a,c,e}={7,5,0} and {b,d,f}={9,2,1}

So, Number of numbers 2×2!×3!=24

Total =60