Math, asked by adityak4m6le007, 1 month ago

The number of all possible matrices of order 3×3 with each entry 0 or 1 is:
(A) 27
(B) 18
(C) 81
(D) 512​

Answers

Answered by snigdhasen723
2

Answer:

The number of elements in a matrix of order 3×3 are 9 .

All the nine elements have to be either 0 or 1 .

So, Number of entries is 2 .

Thus each of the nine elements can be given by either 0 or 1 .

That is, each of the nine elements can be filled in two possible ways. So, we multiply the number of ways of filling up each element spot in the required matrix as the events are happening one after the other. This is called the fundamental principle of counting.

Therefore, the required number of possible matrices of order 3×3 =29=512

Hence, the number of all possible matrices of order 3×3 with each entry 0 or 1 is 512 .

So, the correct answer is “512”.

Step-by-step explanation:

no d

Answered by khushi565148
5

Answer:

There are 9 elements in the matrix. Each elements can be placed in 2 ways is all possible matrices of order 3 x 3 is 29 = 512

Step-by-step explanation:

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