The number of all possible matrices of order 3 by 3 with each entry 0 or 1 is
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We know that the number of element in each 3*3 matrix is 9 , and we have two element 0 and 1 , so using permutation this will be equal to:
1 element in matrix has 2 option either 1 or 2
hence , 2^9=512 possible matrix.
( since 2*2*2*2*2----------18times).
Explanation:
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