Question

The number of aluminium ions present in 0.051g of aluminium oxide is -------------



(a)6.022x 10>20 ions

(b)6.022x10>21ions

(c)6.022x10>22 ions

(d)6.022 x10>23

​

Answer 1

Answer:

c) 6.022 × 10>22 ions

I hope it will be helpful for you.

Thank you for your question.

Answer 2

Answer:

Mole of aluminium oxide (Al2O3) = 2 x 27 + 3 x 16

= 102 g

i.e., 102 g of Al2O3= 6.022 x 1023 molecules of Al2O3

Then, 0.051 g of Al2O3 contains = 6.022 x 1023 / 102 x 0.051 molecules

= 3.011 x 1020 molecules of Al2O3

The number of aluminium ions (Al3+) present in one molecule of aluminium oxide is 2.