Math, asked by april3739, 11 months ago

The number of arbitrary constants in the particular solution of a differential equation of fifth order is what??

Answers

Answered by vivekanand52
5

There will be no arbitrary constant.

Step-by-step explanation:

If we want to get the general solution of a single order differential equation, then we have to integrate the equation for once to get the general solution and hence there will generate one arbitrary constant.

Therefore, for a fifth-order differential equation, we have to integrate five times to get the general solution of it and hence there will generate 5 arbitrary constants.

But, if we consider the particular solution then we put the limits (boundary conditions) in the general solution and then we will get the particular solution and finally there will be no arbitrary constant remaining in the solution. (Answer)

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