Math, asked by Anonymous, 1 year ago

the number of arrangements in which the letters of the word monday be arranged so that the words so formed begin with M and don't end with N is

Answers

Answered by Anonymous
106
_ _ _ _ _ _
No. of choice for 1st letter : 1 (M)
No. of choice for last letter : 4 (≠N,M)
for 2,3,4,5 letters no. of choices : 4,3,2,1
Total words : 1×4×4×3×2×1 = 96 words
Answered by amitnrw
34

the number of arrangements =  96 in which the letters of the word monday be arranged so that the words so formed begin with M and don't end with N

Step-by-step explanation:

MONDAY

6 Different Letters

begin with M Hence position of M is fixed

Now we remain with 5 positions

don't end with N

Hence N can take any position 2 to 5

N can be arranged in 4 Ways

now we left with 4 position & 4 Letters

Which can be arranged in 4! ways

the number of arrangements = 4 * 4!  = 4 * 24 = 96

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