Question

The number of arrangements of the digits 0, 1, 2, ...., 9 are there that do not end
with 8 and do not begin with 3 is
1) 3456200
2) 9456020
3) 81 x 56
4) 8! x 73​

Answer 1

Answer:

please correct your option it should be

4) 8! x 72

Step-by-step explanation:

we have 0 - 9 means 10 numbers..,

but the number of arrangements do not begin with 3 so their are 9 numbers left and do not end with 8 then their are 8 numbers left..,

that means :

= 9 x 8 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1

= 9 x 8 x (8 x 7 x 6 x 5 x 4 x 3 x 2 x 1)

= 72 x 8!

Answer 2

$\huge\fbox\red{A}\huge\fbox\pink{N}\fbox\green{S}\huge\fbox\blue{W}\fbox\orange{E}\huge\fbox\red{R}$

4) 8! x 73