Question

The number of arrangements of the letters in the word SOLAPUR
SO
that consonants and vowels are placed alternately.
a) 4!
b) 3!
c) 4! X 3!
d) 7​

Answer 1

Answer:

In the word 'SOLAPUR', the number of letters is n = 7. Since consonants and vowels are placed alternately, the four consonants must occur at 4 odd places and three vowels must occur at 3 even places.

Answer 2

Answer:

c) 4! × 3!

Step-by-step explanation:

The consonants and vowels are to be placed alternately. There are 3 vowels and four consonants. So first we place the there vowels in alternate positions with four blank spaces in between. .

The number of permutations of the vowels= 3!

The four consonants go into four gaps. The number of those permutations= 4!.

These two sets of permutations are independent of each other. Then the total number of permutations

= 3! × 4!.