Question

The number of atom in 20g of so3 is approximately

Answer 1

Moles present in 20 g of SO3 = 20/ 80.07 = 0.2498 mol.
​Number of molecules = 0.2498 X 6.022 X 1023 = 1.5 X 1023 molecules.
Each mole of SO3 has 6.022 X 1023 molecules.

Answer 2

79 g of SO3 contains 1 mole of molecules or 4 mole atoms(3 mole atoms of oxygen and 1 mole atoms of sulphur).

So,Number of atoms in20 g SO3

=4×6.02×10^23×20÷79 = 6×10^23

Answer=6 × 10^23