the number of atom present in 16g of oxygen is
Answers
Answered by
2
Explanation:
16 g oxygen has 1 mole atoms, that is, 6.022 × 1023 atoms of oxygen
Answered by
1
Answer:
1 mole:32g of o2=6.022*10^23
1/2 mole:16g of o2 =3.011*10^23
Explanation:
it will have 3.011*10^23 molecules
exactly half of the original quantity....
hope it helps you dear
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