the number of atoms in 0.004 g of magnesium will be
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Weight of 1 mole of Mg = 24 g
Weight of 1/6 mole of Mg = 4 g
Weight of 1/6000 mole of Mg = 0.004 g
1 mole = 6.022 × 10²³ atoms
1/6000 moles = 6.022 × 10²³ × 1/6000
= 1.00366 × 10^20 atoms
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Weight of 1/6 mole of Mg = 4 g
Weight of 1/6000 mole of Mg = 0.004 g
1 mole = 6.022 × 10²³ atoms
1/6000 moles = 6.022 × 10²³ × 1/6000
= 1.00366 × 10^20 atoms
Hope it helps you ☺
Please mark as Brainliest ☺
abhishek91:
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Answer:
answer is 10^20
Explanation:
moles =gm/mm*avogadro constant =number of atoms
0.004/24*6.022*10^23 = number of atoms
4/24*6*10^20 = number of atoms
number of atoms =10^20
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