Question

The number of atoms in 1.79g of gold and 0.023g of sodium are equal

Answer 1

Answer:

No. of moles in Na=1/11 and in Mg = 1/12. Therefore no. of atoms is more in Na than Mg

Answer 2

Answer:

Number of atoms in 1.79 grams of gold and 0.023g of sodium are equal  5.5 × 10²¹ atoms and  6.023 ×10²⁰ atoms respectively.

Explanation:

Given, the mass of the gold = 1.79g

We know the molar mass of the gold = 197g/mol

197g of the gold contains  number of atoms = 6.023 × 10²³

1.79grams of the gold contains atoms  $=\frac{6.023\times 10^{23}\times 1.79}{197}$

The number of atoms in 1.79 g of gold $=0.055\times 10^{23} atoms$

                                                                = 5.5 × 10²¹ atoms

Given, the mass of the Sodium = 0.023g

We know the molar mass of the Sodium = 23g/mol

23g of the sodium contains  number of atoms = 6.023 × 10²³

0.023grams of the sodium contains atoms  $=\frac{6.023\times 10^{23}\times 0.023}{23}$

The number of atoms in 0.023g of sodium $=0.006023\times 10^{23} atoms$

                                                                       = 6.023 ×10²⁰ atoms

Therefore, the number of atoms in 1.79g of gold and 0.023g of sodium are equal  5.5 × 10²¹ atoms and  6.023 ×10²⁰ atoms respectively.

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