Question

The number of atoms in 100 g of an fcc crystal with density d = 10 g cm and cel edge as 200 pm is equal
to :
(1) 3 x 1025
(2) 0.5 * 1025
(3) 1 x 1025
(4)2 x 1025​

Answer 1

Answer:

The number of atoms in 100 g of a fcc crystal with denstiy = 10.0g/cm3 and cell edge equal to 200 pm is equal to. ∴100gcontains=6×102312×100=5×1024 atom

Explanation:

this is the answer