Question

The number of atoms in 4.25 g of NH3
approximately:
(1) 4x1023
(2) 2x1023
(3) 1x1023
(4) 6x1023
​

Answer 1

Answer is option no (4).

$\boxed{{6×10}^{23}}$

This number is called Avogadro number for more information use search engine {GOOGLE}.

NH3 is ammonia and it contains 17 molecules and 17 molecules contains atoms in number of $\boxed{{6×10}^{23}} [\tex]</h3><h3></h3><h3> </h3><h3> </h3><h3></h3><h3> . Therefore, In NH3 number of atoms is[tex] {\boxed{6×10}^{23}} </h3><h3>$

[tex]\boxed{6×10}^{23} [\tex]

is answer.

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Answer 2

heyy dude

here is your answer

firstly we find actual mass of NH3

N =14

H=1

14+1×3

17g

no. of moles = given mass ÷ actual mass

= 4.25 ÷17

= 0.25

no. of moles = no. of molecules/ no. of atoms ÷ avagadro number

0.25= no. of atoms ÷ 6.022×10 ki power 23

0.25 ×6.022×10 ki power 23 = no. of atom

1.5055 ×10 ki power 23

Answer = 2) 2× 10 ki power 23 ( approax )