The number of atoms in 4.25 g of NH₃ is approximately _______.
(A) 1 × 10²³
(B) 2 × 10²³
(C) 4 × 10²³
(D) 6 × 10²³
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17g of NH3 -—------6.023×10^23 atoms
1g of NH3 –-----------6.023×10^23÷17
So,4.25g og NH3,—---------6.023×10^23×4.25÷17=1.5×10^23
Ans 1
1g of NH3 –-----------6.023×10^23÷17
So,4.25g og NH3,—---------6.023×10^23×4.25÷17=1.5×10^23
Ans 1
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