Question

the number of atoms in 4.25 of nh

Answer 1

Answer is 6.022×10^23StepsNo.of Moles=Given Mass / Molar MassGiven Mass =4.25 g =17/4gMolar Mass of NH3 = 17g So No.of Moles =17/4 ÷ 17= ¼Therefore No.of atoms=No.of Moles×6.022×10^23×AtomicityAtomicity of NH3 is 4i.e.