Question

The Number of atoms in 4.25g of NH3 :

Answer 1

So 4.25 g ammonia will contain (6.022×10^23×4.25)/17 = 1.5×10^23 number of ammonia molecules. Each molecule contain 4 atoms (1 N atom and 3 H atoms). So 4.25g ammonia will contain 1.5×10^23×4 = 6×10^23 number of atoms.

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Answer 2

Answer:

Given:-

Molar mass NH3 = 14 + 3 × 1 = 17 g/mol

Molar Mass  = 4.25g

To Find:-

Number of atoms

Solution:-

Number of Moles = $\frac{Given \: Mass}{Molar \:  Mass}$

⇒ $\frac{4.25}{17}$

⇒ $0.25 \: Moles$

Number of Atoms = Number of Moles × 6.022 × 10²³ × Atomicity of atoms

Here,

Number of Moles = 0.25 Moles

Atomicity of atoms = 4 ( 1 nitrogen atom and 3 hydrogen atoms)

Number of Atoms = 0.25 × 6.022 × 10²³ × 4

Number of Atoms = 6.022 × 10²³

(Answer)