Question

the number of atoms of oxygen present in 0.2 moles of Na₂CO₃ will be what? please explain answer

Answer 1

1 mole of NA₂CO₃ contains = 3 moles of oxygen atom
we have 0.2 moles of NA₂CO₃ ,
so we will have = 3 * 0.2 
                           = 0.6 mole of O atoms
since 1 mole of O atoms = 6.022 * 10²³ atoms
therefore,
0.6 mole of O atoms = 0.6 * 6.022 * 10²³
                                  = 3.6132 * 10²³ O atoms
therefore in 0.2 moles of NA₂CO₃  number of Oxygen atoms = 3.6132 * 10²³
 i hope that my answer will help u.................................^_^

Answer 2

1 mole of Na2CO3 contains 3 moles of oxygen atoms means 18.066* 10 ^ 23 atoms
0.2 moles of na^2co^3 contains 3.6132 * 10^23 atoms.