The number of atoms of oxygen present in 10.6 g of na2co3 will be
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Mol wt of Na2Co3=46+12+48=106
Moles of Na2CO3= 10.6/106=0.1
3 moles of oxygen = 0.1
1 mole of oxygen = 0.1/3 = 0.033
No of atoms of oxygen
= 0.033*6.023*10^23
= 2 *10^22
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