Question

The number of atoms of oxygen present in 11.2 Litre of ozone at NTP are

Answer 1

One mole of ozone has 6.023×10^23 molecules.

One mole of Ozone has volume 22.4 liter.
So 11.2 liter of ozone is 0.5 mole.

So 0.5 moles of Ozone has 0.5× 6.023×10^23 molecules.

One molecule of ozone has three oxygen atoms.

So total atoms are- 3×0.5×6.023×10^23=9.03×10^23 numbers.

Thanks.
Hope it helps.
Do the full book of this question(it is from RC Mukharjee,I know)

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