Question

The number of atoms of oxygen present in 24 gm of oxygen gas ?

Answer 1

Answer:

9.0345*10^23 atoms

Explanation:

16g of oxygen contains avagadro number of atoms.                                                              so,16g of 'O'-------> avagadro no.of atoms(Na)                                                                      for,24g of 'O'---------> x(say).                                                                                                by calculating through criss cross method x=24*Na/16                                                    which is equal to 9.0345*10^23 atoms

Answer 2

Answer:

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