Question

The number of atoms of oxygen present in the same number of moles of baking soda as are present in 100 g of glucose (C6H12O6) is approximately


9.9126 × 1020


19.1261 × 1023


8.1121 × 1023


9.9363 × 1023

Answer 1

we have to find the number of atoms of oxygen present in the same number of moles of baking soda are present in 100g of glucose.

solution : molecular weight of glucose = molecular weight of C₆H₁₂O₆ = 180 g/mol

given weight of glucose = 100g

so, no of moles of glucose = 100/180 = 5/9

a/c to question,

no of moles of baking soda = no of moles of glucose = 5/9

so, no of moles of oxygen atoms = 3 × 5/9 = 1.66

[ as we see, chemical formula of baking soda is NaHCO₃ means, in one mole of Baking soda three moles of oxygen atoms are present]

now no of oxygen atoms = 1.66 × Avogadro's number

= 1.67 × 6.023 × 10²³

= 9.9818 × 10²³ it is nearest value of 9.9363 × 10²³

Therefore correct option is (4) 9.9363 × 10²³