Question

The number of atoms of oxygen present in the
same number of moles of baking soda as are
present in 100 g of glucose (C6H120.) is
approximately​

Answer 1

Molecular formula =C  

6

​  

H  

12

​  

O  

6

​  

 

Molar mass =6×12+12×1+16×6=180gmol  

−1

 

Moles in 18g of sample=  

180

18

​  

=0.1mole

So,moles of carbon present in sample=0.1×6=0.6

Moles of hydrogen=0.1×12=1.2

Moles of oxygen=6×0.1=0.6

No. of atoms present in carbon=0.6×6.022×10  

23

=3.6×10  

23

 

No. of atoms present in hydrogen=1.2×6.022×10  

23

=7.2×10  

23

 

No. of atoms present in oxygen=0.6×6.022×10  

23

=3.6×10  

23

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