the number of atoms present 18g of glucose will be
glucose formula C6H12O6
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Answer: The molar mass of glucose is 180 g/mol.
So the total number of moles = 18/180 = 0.1
which gives total number of molecules = 0.1 * 6.02. *10^23
= 6.02*10^22
Now one molecule of glucose has 24 atoms so total number of atoms are 24 * 6.02 * 10^22
= 1.44 * 10^24 atoms
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