Question

The number of atoms present in 0.05g of
water is
(A) 1.67 × 1023 (B) 1.67 × 1022
(C) 5.02 × 1021 (D) 1.67 × 1021

Answer 1

molecular mass of water = 18

and no. atoms present in 18 g = 3× 6.022 *10²³

and no of atoms in 1 g = 3× 6.022* 10 ²³/ 18

therefore

no. atoms in 0.05g = 3× 6.022 *10²³ × 0.05 / 18

Answer 2

Explanation:

answer

D is correct

correct