Question

The number of atoms present in 0.1 mole of P4 ( atomic mass 31) are
a) 2.4 × 10^24 atoms
b) same as in 0.05 mole of S8
c) 6×10^22 atoms
d) same as in 3.1 gram of phosphorus

Answer 1

Answer:

d) same as in 3.1 gram of phosphorus

Explanation:

no. of atoms = atomicity × Avogadro number × no. of moles

                      = 4× 6.022 × 10²³ ×0.1

                      = 24.088 × 10²² atoms

1 mole of phosphorous contains 31g

therefore 3.1 g of phosphorous contains 0.1  moles

hence 3.1 gram of phosphorus contains 24.088 × 10²² atoms

Answer 2

Answer:

Explanation:

0.1 mole p4 contains

=4×0.1×6.02×1023P atoms

0.05 mole of S8 contains

=8×0.05×6.02×1023s atom