Question

the number of atoms present in 0.1 mole of P4 (atomic mass= 31)

Answer 1

Hello Mate!

Atomic mass of P is 31 g/mol

Then melcular mass of P4 i.e, will be equal to 4 atoms of P.

Since we know that,

1 mole of P = 6.022 × 10²³

0.1 mole of P = 6.022 × 0.1 × 10²³

0.1 mole of P = 0.6022 × 10²³

0.1 mole of P = 6.022 × 10²²

Now, 0.1 mole of P4 i.e, 4 atoms of P = 4 × 6.022 × 10²²

0.1 mole of P4 = 24.088 × 10²²

0.1 mole of P4 = 2.4088 × 10²³

0.1 mole of P4 = 2.41 × 10²³

Thanks!

Have great future ahead!

Answer 2

here is your answer ☺☺☺☺☺

Number of Atoms = N

Number of moles = n

Avagadro's No. = NA

n = N/NA

0.1 = N/ 6.022*1023

N = 0.1 * 6.022*1023

N = 6.022*1022

So Number of atoms = 6.022*1022

thanks