the number of atoms present in 0.1mol of tetraatomic gas is
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Given :
Atomicity of moelucle is 4
Avogadro Number=6.022x 10²³ atoms
0.1 mole of gas available.
Number Of atoms=Mole x Avogadro number x atomicity of molecule
=0.1 x 6.022x 10²³ x 4
=2.40 x 10²⁸ atoms
∴Number of atoms in 0.1 mole of a tetra-atomic gas is 2.40 x 10²⁸ atoms
Atomicity of moelucle is 4
Avogadro Number=6.022x 10²³ atoms
0.1 mole of gas available.
Number Of atoms=Mole x Avogadro number x atomicity of molecule
=0.1 x 6.022x 10²³ x 4
=2.40 x 10²⁸ atoms
∴Number of atoms in 0.1 mole of a tetra-atomic gas is 2.40 x 10²⁸ atoms
Answered by
1
✨Number of atoms = Mole × Avogadro number x atomicity of molecule.
= 0.1 × 6.022 × 10²³ × 4
= 2.40 × 10^28 atoms.
✨Therefore, Number of atoms in 0.1 mole of tetra-atomic gas is 2.40 × 10^28 atoms.
= 0.1 × 6.022 × 10²³ × 4
= 2.40 × 10^28 atoms.
✨Therefore, Number of atoms in 0.1 mole of tetra-atomic gas is 2.40 × 10^28 atoms.
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