Chemistry, asked by justu8496, 7 hours ago

the number of atoms present in 0.25 mole of nh3

Answers

Answered by Anonymous
3

Explanation:

Refer to the attachment

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Answered by Anonymous
67

Answer:

Weight of NH3 = 0.25 g

Number of moles of

NH3 =  \frac{weight}{molecular \: weight}

 =  \frac{0.25}{17}

 = 0.014

Number of molecules in 0.25 mole of NH3

 = 0.25 \times 6.023 \times  {10}^{23}

So, number of atoms

 = 4 \times 0.25 \times 6.023 \times  {10}^{23}

 = 6.0 \times  {10}^{23}

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