Question

the number of atoms present in 0.25 mole of nh3

Answer 1

Explanation:

Refer to the attachment

Answer 2

Answer:

Weight of NH3 = 0.25 g

Number of moles of

$NH3 = \frac{weight}{molecular \: weight}$

$= \frac{0.25}{17}$

$= 0.014$

Number of molecules in 0.25 mole of NH3

$= 0.25 \times 6.023 \times {10}^{23}$

So, number of atoms

$= 4 \times 0.25 \times 6.023 \times {10}^{23}$

$= 6.0 \times {10}^{23}$