Question

the number of atoms present in 10 gms of CaCO3
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Answer 1

Explanation:

amak S jffjjdndj E dnnffnjd X ndndnd

Answer 2

Answer:

Explanation:

Mass of caco3 is 100g

thus 100g makes a mole

so 10g makes 0.1 mole

no of molecules in 0.1 mole = 0.1 x 6.023 x 10²³molecules.=6.023 x 10²² molecules.

1 molecule has Ca, C, O, O, O =5 atoms

thus 6.023 x 10²² molecules has 5 x 6.023 x 10²²=3.0115 x 10²³