Question

the number of atoms present in 10 gms of caCO3​

Answer 1

Answer:

0.5x6x10^23 atoms

Explanation:

100g of CaCo3 contains 5x6x10^23 atom

1g contains (5x6x10^23)/100 atoms

so 10g contains

(5x6x10^23)x10/100

=0.5x6x10^23