the number of atoms present in 10 gms of caCO3
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Answer:
0.5x6x10^23 atoms
Explanation:
100g of CaCo3 contains 5x6x10^23 atom
1g contains (5x6x10^23)/100 atoms
so 10g contains
(5x6x10^23)x10/100
=0.5x6x10^23
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