Question

The number of atoms present in 16 g of oxygen is​

Answer 1

Answer:

6.023*10to the power 24

Explanation:

O2

16*2

32

16/32*6.023*10²³

0.5*6.023*10²³(now 1 molecules of oxygen contains 2 atoms )

2*0.5*6.023*10²³

10*6.023*10²³

6.023*10 to the power 24