Question

The number of atoms present in 71 g of Cl, is:
Options :

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Answer 1

Answer: 2 mole atoms

=2 × 6.022×10^23 atoms

Explanation:

No. Of moles =given mass/atomic mass

=71 / 35.5

= 2 moles

=2 × 6.022×10^23 atoms

Answer 2

Answer:

Explanation:

71/35.5 *6.022*10^23-avogadro no.

35.5 is molar mass and 71 is given

After mutiply it will be 12.044*10^23