The number of atoms present in one mole of an element is equal to Avogadro number. Which of the following element contains the greatest number of atoms?
(i) 4g He
(ii) 46g Na
(iii) 0.40g Ca
(iv) 12g He
Answers
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2
Answer:46g of Na
Explanation:46 is a greater number and Sodium has an atomic mass number of 11 becoming only the smaller one following calcium which got a 0.40 and that makes sodium to gave the highest number of atoms
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16
Explanation:
iv) 12g He contains more no.of atoms.
No.of moles = No.of given atoms/avagadro
no.of atoms
No.of atoms = No.of moles × avagadro no.
(i) no.of atoms = 4g/4g × No = 1No
(ii) no.of atoms = 46g/23g × No = 2× No
(iii) no.of atoms = 0.40/40 ×No = 0.1 ×No
(iv) no.of atoms = 12g/4g × No = 3×No
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