Question

The number of atoms present in one mole of an element is equal to Avogadro number. Which of the following element contains the greatest number of atoms?
(i) 4g He
(ii) 46g Na
(iii) 0.40g Ca
(iv) 12g He

Answer 1

Answer:46g of Na

Explanation:46 is a greater number and Sodium has an atomic mass number of 11 becoming only the smaller one following calcium which got a 0.40 and that makes sodium to gave the highest number of atoms

Answer 2

Explanation:

iv) 12g He contains more no.of atoms.

No.of moles = No.of given atoms/avagadro

no.of atoms

No.of atoms = No.of moles × avagadro no.

(i) no.of atoms = 4g/4g × No = 1No

(ii) no.of atoms = 46g/23g × No = 2× No

(iii) no.of atoms = 0.40/40 ×No = 0.1 ×No

(iv) no.of atoms = 12g/4g × No = 3×No