Question

The number of atoms present in one mole of an element is equal to Avogadro number. Which of the following element contains the greatest number of atoms?and how?​

Answer 1

12 g helium

Explanation:

Correct option is

D

12 g He

Number of moles=n=

molecular weight

weight

1. 4 g He⇒

4

4

=1 mole

2. 46 g Na⇒

23

46

=2 moles

3. 0.4 g Ca⇒

40

0.4

=0.01 moles

4. 12 g He⇒

4

12

=3 moles

Number of moles ∝ number of atoms

Therefore 12 g He contains greatest number of atoms.

Hope it helps