The number of atoms presents in one mole of an element is equal to avogadro number which of the following elements contains the greatest no. Of atoms (a) 4g He (b) 46g Na (c). 40g Ca (d) 12g He
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the number of atoms present in one mole of an element is equal to 6 into 10 to the power 22.
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the answer is 12g of helium it contains 3 ×6.023 ×10^23atoms of helium
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