Question

the number of aways in which 4 children can occupy 4 chairs is ​

Answer 1

Total chairs =7

To select 4 conservative chairs,

No. of ways =7−4+1

(n−r+1)

=4

To arrange 4 students at these 4 chairs

No. of ways =4!

⇒ Total No. of arrangements =4×4!

Answer 2

The number of ways 4 children can occupy 4 chairs is 4! = 24 ways.

It is given that there are 4 chairs and 4 children.

So for the first child, the number of ways of occupying a chair is 4

After the first child takes a seat the number of empty chairs left are 3, so the number of ways the second child can take a seat is 3

Similarly, for the third child the number of possible ways will be 2 and then 1 for the fourth child.

Therefore the total number of ways 4 children can occupy 4 seats will be

= 4 x 3 x 2 x 1 = 24

Hence, the number of ways 4 children can occupy 4 seats is 24.