The number of bacteria in a certain culture doubles every hour. If there
were 30 bacteria present in the culture originally, how many bacteria will
be present at the end of 2nd hour, 4th hour and n
th hour?
Answers
Answered by
0
Step-by-step explanation:
Bacteria at the end of 2nd hour = 30 X 2^2
Bacteria at the end of 4th hour = 30 X 2^4
Bacteria at the end of nth hour = 30 X 2^n
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Answered by
2
According to the question,
30, 60, 120, 240....
This is GP with a = 30 and r = 2
Bacteria present after 2 hours = a3
a3 = ar2 = 30 (2)2 = 120
a5 = ar4 = 30 (2)4 = 480
Baceria present after n hours = an + 1
an = arn + 1 - 1 = 30 (2n)
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