Question

The number of bijection functions set contains 5 elements are
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Answer 1

Answer:

Answer is 120

Step-by-step explanation:

Here, It is given that

n(A) = 5

For Bijection: Function must be one-one and onto simultaneously.

Also, Bijection is only possible when no. of elements in both the sets is same.

And is given by :  [ n(A) ]!

Here,  f is a function from A to A

Hence, Bijection is possible ( Because, n(A)=n(A) )

Now,

No. of bijective functions = (5)! = 5*4*3*2*1=120

Hence Answer is 120