Physics, asked by jyotiatulpawar6678, 1 month ago

the number of bonds formed in p-type and n-type semiconductors are respectively​

Answers

Answered by archithasenthilkumar
1

Answer:

Explanation:Pentavalent impurities Impurity atoms with 5 valence electrons produce n-type semiconductors by contributing extra electrons. Trivalent impurities Impurity atoms with 3 valence electrons produce p-type semiconductors by producing a "hole" or electron deficiency.

Answered by KaurSukhvir
0

Answer:

In p-type semiconductor, three bonds are formed. In n-type semiconductor, four bonds are formed between doped atom and atom of crystal.

Explanation:

The conductivity of some semiconductor is very low. To increase their conductivity, we add some impurities.

  • P-type semiconductor : The addition of atoms of group 13 as impurity in the pure crystal of element of group 14.  Because atom of group 13 has only three valence electrons. So, it will form only three bonds with the atoms of group 14. As a result, holes will be created For e.g. if we doped  aluminium in the pure crystal of silicon.
  • N-type semiconductor : When we add atoms of group 15 as impurity in the pure crystal of element of group 14. Now, atom of group 15 has five valence electros. So, it will form only four bonds with the atoms of group 14. As a result, extra electrons get introduced in the crystal.  For e.g. if we doped  phosphorous in the pure crystal of silicon.

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