the number of boy and girls in a class are in the ratio 7:5 the the number of boys is 8 and more than the number of girls. what is the total class strength?
Answers
Answer:
let ratio=x
number of boys=7x
number of girls =5x+8
5x+8=7x
5x-7x=-8
-2x=-8
x=4
:.number of boys=7x=7*4=28
number of girls=5x+8=5*4+8=20+8=28
Given:
The number of boy and girls in a class are in the ratio 7:5.
The number of boys is 8 and more than the number of girls.
To find:
Total number of strength of the class.
Solution:
The number of boy and girls in a class are in the ratio 7:5.
Let, the common multiple of the ratio be, 'n'.
∴ The number of boys in the class_
(7×n)
= 7n
∴ The number of girls in the class _
(5×n)
= 5n
The number of boys is 8 and more than the number of girls.
∴ According to the problem:
(7n-5n) = 8
⇒ 2n = 8
⇒ n = (8÷2)
⇒ n = 4
∴ The number of boys in the class_
(7×4)
= 28 boys
Similarly,
The number of girls in the class_
(5×4)
= 20 girls
∴ Total number of strengths in the class is_
(28+20)
= 48 strengths.
∴ The total number of strengths in the class is 48.
Answer:
Total number of strengths in the class is 48.