Question

the number of boys and girls in a class are in the ratio 5 : 3 the number of girls is 10 more than the number of boys what is the class strength​

Answer 1

Step-by-step explanation:

Let the common ratio between number of boys and girls be x

Number of boys =7x

Number of girls =5x

As per the question,

Number of boys = Number of girls +8

7x=5x+8

Transpose 5x to LHS, we will get

7x−5x=8

2x=8

Divide both sides by 2

x=4

No. of boys =7x=7×4=28

No. of girls =5x=5×4=20

Total class students 28+20=48

Answer 2

$\huge\underbrace\mathfrak\color{red}{ †\: Question:–}$

The number of boys and girls in a class are in the ratio 5 : 3 the number of girls is 10 more than the number of boys what is the class strength.

$\huge\underbrace\mathfrak\color{red}{ †\: Answer:–}$

Given ;

The number of boys and girls in a class are in the ratio 5 : 3 .

$~~~~~~~~~~~\frac{Number \:of \:boys}{Number \:of \:girl}$ = $\frac{5}{3}$

So let the boys strength be = 5x

And let the girls strength be = 3x

Given ;

The number of girls is 10 more than the number of boys .

Number of boys = Number of girl × 10

$~~~~~~~~~~~~~~~~~~~~~→ 5x = 3x + 10$

$~~~~~~~~~~~~~~~~~~~~~→ 5x - 3x = 10$

$~~~~~~~~~~~~~~~~~~~~~→ 2x = 10$

$~~~~~~~~~~~~~~~~~~~~~→ x = \frac{10}{2}$

$~~~~~~~~~~~~~~~~~~~~~→ x = \frac{\cancel10^{5}}{\cancel2_{1}}$

$~~~~~~~~~~~~~~~~~~~~~→ x = 5$

Therefore ;

Number of boys = 5x = 5(5) = 25

Number of girls = 3x = 3(5) = 15

Total class strangth = Number of boy + Number of girl

$~~~~~~~~~~~~~~~ = 25 + 15 = 40$

$~~~~~~~~~~~~~~~= 40$

Total class strangth = 40 student