Question

the number of boys and girls in a class are in the ratio 7.5 the number of boys is 8 more than the number of girls what is the total class strange​

Answer 1

Correct Question :

• The number of boys and girls in a class are in the ratio 7 : 5 . The number of boys is 8 more than the number of girls what is the total class strength.

Solution :

Let the no. of girls in class be x and no. of boys in class be (x+8)

According to the Question :

$\longrightarrow \sf \: 7\: \times\: x = (x + 8) \times 5$

$\longrightarrow \sf \: 7x = 5x + 40$

$\longrightarrow \sf \: 7x - 5x = 40$

$\longrightarrow \sf \: 2x = 40$

$\longrightarrow \sf \: x = \cancel\dfrac{40}{2}$

$\longrightarrow \sf \red{x = 20}$

Hence,

• Number of girls in the class = 20

•Number of boys = (20+8) = 28

★ Total Strength of Class = Total Boys + Total Girls

→ Total Strength = 28 + 20

→ Total Strength = 48

$\therefore$ Total Strength of class is 48

Answer 2

Answer:

☯ $\boxed{\sf The\:total\:strange\:of\:class\:is\:48}$

Step-by-step explanation:

$\longrightarrow\large\textsf{Let\:the\:number\:of\:girls\:in\:a\:class = x}$

$\longrightarrow\large\textsf{Let\:the\:number\:of\:boys\:in\:a\:class = (x + 8)}$

☯ According To The Question (ATQ) :

$\longrightarrow\large\textsf{7x = 5(x + 8)}$

$\longrightarrow\large\textsf{7x = 5x + 40}$

$\longrightarrow\large\textsf{7x - 5x = 40}$

$\longrightarrow\large\textsf{2x = 40}$

$\longrightarrow\large\mathrm\purple{x = 20}$

☯ Now :

$\longrightarrow\large\mathrm\red{Number\:of\:girls = 20}$

$\longrightarrow\large\mathrm\red{Number\:of\:boys = (20+8)}$

☯ Total Strange Of Class :

$\longrightarrow\large\textsf{Girls = 20}$

$\longrightarrow\large\textsf{Boys = 28}$

$\longrightarrow\large\mathrm\purple{Total\:strength = 20 + 28 = 48}$