Math, asked by itzcutiepie2400, 4 months ago

the number of boys and girls in class are in ratio 7 ratio 5 the number of boys is 8 more than number of girls what is the total class strength​.



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Answers

Answered by Anonymous
11

 \huge{ \underline{ \underline \mathfrak \red{Answer - }}}

Let the number of boys be 7x and that of girls be 5x.

According to the given condition, we have

Number of boys = Number of girls +8

⟹7x=5x+8

⟹7x−5x=8 ....[Transposing 5x to LHS]

Therefore, number of boys =7x4=28 and number of girls = 5x4=20

So, total number of children in the class =28+20= 48.

Hence, the class strenght is 48.

Answered by pavneet24
29

GIVEN:-

  • Ratio of number of boys to number of girls is 7:5
  • Number of boys is 8 more than number of girls

TO FIND:-

  • Total strength of the class

SOLUTION:-

Let

  • Number of boys be 7x
  • Number of girls be 5x

We are given,

Number of boys is 8 more than than number of girls

 \implies7 \sf{x} = 5 \sf{x}  +  8

 \implies7 \sf{x} - 5 \sf{x} = 8

 \implies2 \sf{x} = 8

 \implies \sf{x} =  \frac{8}{2}

 \implies \sf \red{x = 4}

Then,

Number of boys

 = 7 \sf{x = 7(4) = 28}

Number of girls

 = 5 \sf{x = 5(4) = 20}

Total class strength = Number of girls + Number of boys

 \implies\sf{total \: class \: strength = 20 + 28}

 \implies \sf \blue{total \: class \: strength = 48}

Total Strength of The class is 48

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