Question

The number of boys and girls ina class are in the ratio7:5.The numberof boys is 8 more than the number of girls .What is the total class strength

Answer 1

Given :-

the ratio between the no. of boys and girls in a class is 7 : 5

let the no. of boys and girls be 7x and 5x respectively.

ATQ,

the no. of boys in the class is 8 more than the no. of girls.

therefore, 5x + 8 = 7x

➡ 5x - 7x = -8

➡ -2x = -8

➡ x = -8/-2

➡ x = 4

» the total no. of girls = 5x

= 5 × 4

= 20 girls

» the total no. of boys = 7x

= 7 × 4

= 28 boys

hence, the total strength of the class = 20 + 28

= 48 students

Answer 2

$\bf{\huge{\underline{\boxed{\tt{\blue{Answer:}}}}}}$

As per the first condition :-

• The number of boys and girls ina class are in the ratio7:5.

Let x be the common multiple of this ratio,

•°• number of boys = 7x

number of girls = 5x

No. of boys :No. of girls = 7x : 5x

According to second condition:-

• The numberof boys is 8 more than the number of girls

The equation forms as follows :

7x = 5x + 8

7x - 5x = 8

2x = 8

x = $\bf\large\frac{8}{2}$

•°• x = 4

The value of the common multiple, x = 4

No. of boys = 7x = 7 × 4 = 28 boys.

No. of girls = 5x = 5 × 4 = 20 girls.

We are asked to find the total strength of the class,

$\bf{\boxed{\red{Total\:strength\: of\:class\: =\: No.\: of\: boys\: + No.\: of \:girls\:}}}$

Total strength of the class = 28 + 20

Total strength of the class = 48 students.

$\bf{\large{\underline{\blue{\tt{Total\:no. of\:students = 48\:students}}}}}$