Math, asked by sanoop999, 8 months ago

The number of boys and the girls in the class are in the ratio 7:5. The number of boys is eight more than the number of girls. What is the total class strength? Answer with proper explanation ya main report karun ......

Answers

Answered by nikitasinghmar46
2

Hello

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Let the number of boys be 7x and that of girls be 5x.

According to the given condition, we have

Number of boys = Number of girls +8

⇒7x=5x+8

⇒7x−5x=8 ....[Transposing 5x to LHS]

⇒2x=8

⇒x=

2

8

=4

Therefore, number of boys =7×4=28 and number of girls =5×4=20

So, total number of children in the class =28+20=48.

Hence, the class strength is 48.

Answered by Anonymous
7

Given:

  • Ratio of number of boys to girls = 7:5
  • Number of boys more than girls = 8

To Find:

Total strength of the class.

Solution:

Let us consider the number of boys be 7x and girls be 5x

According to the question,

7x=5x+8\\\implies 7x-5x=8\\\implies 2x= 8

Now, finding the value of x

\implies x=\frac{8}{2} \\\implies x= \boxed{4}

∴ Number of boys = 7 \times 4 =\boxed{28}

Number of girls = 5 \times 4 = \boxed{20}

Total number of students = 20+28= \boxed{48}

Thus, the number of boys are 28, girls are 20 and the total number of students are 48.

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