Question

the number of boys at a childcare centre was 7/12 of the number of girls. there were 125 more girls than boys. after 75 boys left.how many boys remained at the childcare centre?

Answer 1

Answer:

102

Step-by-step explanation:

let the girls= x

boys = 7x/12

x-7x/12 = 125

x = 300

boys = 300× 7/12 = 177

now remaining boys = 177 - 75 = 102

Answer 2

Given :-

• The number of boys at a child care center was 7/12 of the number of girls.
• The number was girls were 125 more than the boys
• 75 boys left after sometime

Aim :-

• To find the number of boys remaining at the childcare center after 75 left.

Let the number of boys be x

According to the question,

$Girls = 125 + x$

$Boys = \dfrac{7}{12} \times (125 + x)$

Let us form a Equation.

According to the question,

$x = \dfrac{7}{12} \times (125 + x)$

[x representing the number of boys]

$x = \dfrac{875 + 7x}{12}$

Transposing 12 to the LHS (Left Hand Side),

$12(x) + 875 + 7x$

$12x = 875 + 7x$

Transposing 7x to the LHS(Left Hand Side),

$12x - 7x = 875$

$5x = 875$

Transposing 5,

$x = \dfrac{875}{5}$

$x = 175$

75 leave the center,

Number of boys after 75 leave = 100 (175-100)

Verification :-

Let us verify the equation we formed before:-

$x = \dfrac{7}{12} \times (125 + x)$

$175 = \dfrac{7}{12} \times 300$

By cancellation,

$175 = 7 \times 25$

$LHS = RHS$

Therefore Verified.